AMP na naman /heh
….continued
kilowatt-hour, took me some time to ponder how to remove the hour in the equation. If not for Tina, I woudnt get the formula to solve my problem.
To understand better, lets examine how our Meralco compute for our electric bill. A typical example would be a Flat iron that has 700watts rating. So the formula is:
[Power * hour ] / 1000 = kilowatt-hour
so, the only variable is the hour, if we use our flat iron for a duration of 4hours, thus the usage will be.
[(700 * 4) = 2800 / 1000] = 2.8 Kilowatt-hour!
Ding, that rings the bell… so to calculate for my AMP!!! all I need to do is to reverse the order.
(Power * Hour) / 1000 = Kilowatt-hour
Power * Hour = Kilowatt-hour * 1000
Power = (Kilowatt-hour * 1000) / Hour
Therefore:
AMP = Power / Voltage (220)
Problem solved ! ! ! !
Actually… this problem wouldnt be a big one if only I had look for the right resource.
http://en.wikipedia.org/wiki/Watt-hour its all in the wikipedia /heh
Go ahead, try to compute your Meralco bill using your refrigerator as a basis and check how much it consumes per month.






2 comments
nice one, quite informative
Wow, your math discussion just gave me a headache.
It’s been ages since I last dealt with electronics math–with any type of math for that matter. All I do nowadays is arithmetic, and not too well, even.
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