Category — Work Related

No, this is not about summer that is fast approaching, where you can think of basking under the summer sun. Crystal clear water, white beaches or even company outings.

This one is a serious problem facing all household today! It happened during the early days when we move to our new apartment.

In case of fire and worse, when a building is totally reduced to ashes, the flourescent ballast may not be listed among the primary suspects for electrical triggers.

The picture above clearly illustrates the incident which prompted me to replace all defective electrical lighting components in our apartment that may start a fire .

So you too, should ask yourselves, when was the last time you fixed or replaced any electrical systems in your place? If you haven’t, its time to check and do something about it to avoid any possible fire tragedies.

….continued

kilowatt-hour, took me some time to ponder how to remove the hour in the equation. If not for Tina, I woudnt get the formula to solve my problem.

To understand better, lets examine how our Meralco compute for our electric bill. A typical example would be a Flat iron that has 700watts rating. So the formula is:

[Power * hour ] / 1000 = kilowatt-hour

so, the only variable is the hour, if we use our flat iron for a duration of 4hours, thus the usage will be.

[(700 * 4) = 2800 / 1000] = 2.8 Kilowatt-hour!

Ding, that rings the bell… so to calculate for my AMP!!! all I need to do is to reverse the order.

(Power * Hour) / 1000 = Kilowatt-hour
Power * Hour = Kilowatt-hour * 1000
Power = (Kilowatt-hour * 1000) / Hour

Therefore:

AMP = Power / Voltage (220)

Problem solved ! ! ! !

Actually… this problem wouldnt be a big one if only I had look for the right resource.

http://en.wikipedia.org/wiki/Watt-hour its all in the wikipedia /heh

Go ahead, try to compute your Meralco bill using your refrigerator as a basis and check how much it consumes per month.

For more than 7 years of handling Internet Data Center (IDC) operations, who would ever thought that I’ll be ask about ampere? AMP!? thats easy, just follow the formula P = V x I, to get the Current (I) = P/V! Voila, problem is solved!!! or is it? But what if you are only given the Kilowatt-hour? Thats when my problem started.

Faced with a dilemma of computing for the AMP with only the kilowatt-hour reading from the power distrubution, I began scouring the Internet and came up empty. An hour passed and by this time, my boss is already knocking on my ass  demanding for the information!

The deadline is upon me looming like a dark cloud ready to strike with a murderous lightning!   Seach engines, which should be the magical force in this computer age for all sorts of remedy, failed to deliver the right solution!  

Then, something clicked…  the Ozph connection! I suddenly remembered that a fellow Electrical Engr. is a loyal Oz player, Tina. I asked her if she still remembers how to compute for the AMP with only the kilowatt-hour in hand, after few minutes of silence, she gave the explanation that nobody else could provide.  Hurrah for the Oz Player!

Problem solved… Yahhh.. antok na.. @.@ bukas na ulit… para may suspense paano ko na compute /gg

hmmm.. with so many space in my personal web space…..

i guess blogging would be nice idea, updating pictures and a lot more…